We’re going to be looking at Ohm’s Law to understand how it works as well as how to use it. There are also two problems at the end of this article for you to test your knowledge and see if you can solve.

## So, what is Ohm’s Law?

Ohm’s Law is a relationship between voltage, current, and resistance and how they relate to each other. Ohm’s Law was developed by German physicist, named Georg Ohm, who undertook many experiments to develop his theory.

Measuring current by touching the live electrical circuits to see how much it hurt. As you might imagine, the higher the current, the more it hurt.

Now, there are three formulas we need to use for Ohm’s Law, but we don’t actually need to remember these and I’ll show you a super easy tip in just a moment.

## Formula of Ohm’s law

So, the three formulas we use for Ohm’s Law are, voltage equals current multiplied by resistance, current equals voltage divided by resistance, resistance equals voltage divided by current.

V=IR

If that seems like a lot to remember, then don’t worry, because we don’t need to remember them. All we need to remember is Ohm’s triangle, which looks like this.

So, you just need to remember these three letters in order. V-I-R. Then we just write those down in a triangle with V at the top and we draw a line to separate the letters.

Now, all we do when we need to use a formula is cover up the letter we need. So, if we want to find the voltage, then we write V = and then we cover up the V in the triangle. That leaves us with I and R, so we write I multiplied by R, which means voltage equals current multiplied by resistance.

You can write a little multiplication symbol in the triangle between the two letters if it helps you. Now, I know what you’re thinking.

## Why is current represented with a letter I and not a C for current?

Or even a letter A for the unit of Ampere. Well the unit of current is the Ampere or the Amp and this is named after Andre Ampere, a French physicist. couple of hundred years ago, he undertook lots of experiments, many involved varying the amount of electrical current.

So, he called this intensite du courant or the intensity of current. So, when he published his work, they took the letter I and it became standard until this day. Now, you might also come across formulas where the letter E is used instead of V.

The letter E stands for EMF, or Electromotive Force, but don’t worry about that, just stick to using V and substitute V for E if you see it used in Ohm’s Law’s questions. Anyway, so by covering V, we get voltage equals current multiplied by resistance.

If we want to find current then we write down I = and then we cover up the letter I in the triangle. That gives us V and R, so as V is above the R like a fraction we can write V divided by R. Therefore, current is equal to voltage divided by resistance.

If we want to find resistance, then we write down R =  and then we cover up R in the triangle. That leaves us with V and I. So, we write V divided by I, which gives us resistance equals the voltage divided by current.

Let’s look at some examples for how to use these formulas. First, let’s see how we find voltage and how it relates to the other parts. Let’s say we have a simple electrical circuit with a battery and a resistor. We don’t know what the voltage of the battery is though.

The resistor is 3 Ohms and when we connect a multi meter into the circuit, we see that we get a reading of two Amps of current. We want to find the voltage. So, using Ohm’s triangle, we can cover up the V and that gives us V equals I multiplied by R.

We know the current is two Amps so we can write that in and we know the resistance is three Ohms, so we can write that in also. Therefore, two Amps multiplied by three Ohms, gives us six volts. The battery is therefore six volts.

Now, if you want to check your answers for Ohm’s questions, then I’ve built a free calculator on the website. You can just drop your numbers in and it will do the calculation for you.

## Example for Ohm’s law

if we now double the voltage by connecting two six volt batteries in a series, we get 12 volts. If we now connect this to the same circuit, the current also doubles from two Amps to four Amps. If we double the voltage again to 24 volts, the current will also double to eight Amps.

So, what’s the relationship here?

We can see that current is therefore directly proportional to voltage. If we double the voltage, we double the current. Remember, voltage is like pressure, it’s the pushing force in the circuit.

It pushes the electrons around the wires and we place things like lamps in the way of these electrons so that they have to flow through these and that causes the lamp to light up.

By doubling the voltage we see that the current also doubles, meaning that more electrons are flowing and this occurs as we apply more pressure or more voltage. This is just like if we were to use a bigger water pump then more water will flow.

Okay, so what about finding current? Let’s say we now have a three Amp lamp connected to a six volt power supply. To find the current, we write down I = and then we cover up I in the triangle.

That gives us V divided by R, so current equals voltage divided by resistance. We know the voltage is six volts and the resistance is at three Ohms, so the current is therefore two Amps and that’s what we see on the multi-meter.

By the way, if you don’t have a multi-meter then I highly recommend you get one. It’s essential for troubleshooting, but also building your essential electrical knowledge. I will leave some links down below for which one to get and from where.

So, we saw what happens when we use a resistance of three Ohms in the circuit, but if we double the resistance to six Ohms by placing another three Ohm lamp into the circuit, the current halves are just one Amp.

If we double the resistance again to 12 Ohms, the current will half again to .05 Amps. We can visually see this because the lamps will become less bright as the current reduces from the increase in resistance.

## So, what’s the relationship here?

We can see that the current is inversely proportional to the resistance. When we double the resistance, the current will decrease by half. If we half the resistance the current will double. Current is the flow of electrons or the flow of free electrons.

For us to make this lamp shine, we need to push electrons through it. How do we do that? We apply a voltage across the two ends. The voltage will push the electrons.

The atoms inside the copper wire have free electrons in their valance shell, which means they can very easily move to other copper atoms. They will naturally move to other atoms by themselves, but this will be in random directions, which is of no use to us.

For the lamp to turn on, we need lots of electrons to flow in the same direction. When we connect a voltage source, we use the pressure of a battery to push the electrons through the circuit all in the same direction.

## Another example for Ohm’s law

to power this 1.5 Ohm resistive lamp, with a 1.5 volt battery, requires one Amp of current .This is equal to six quintillion, two hundred and forty two quadrillion electrons passing from the battery and through the lamp every second.

And if you can achieve this, then the lamp will stay at full brightness. If the voltage or current reduces or the resistance of the circuit increases, then the lamp will become dimmer. Okay, now let’s look at finding resistance.

Say we have a resistive lamp connected to a 12 volt power supply. We don’t know how much resistance is adding to the circuit, but we measure the current at 0.5 Amps. To find the resistance, we write down R = and then we cover up the R in the triangle.

We’re left with V and I, so resistance equals voltage divided by current. We know the voltage is 12 volts and the current is 0.5 Amps, so 12 divided by 0.5 gives us 24 Ohms of resistance. Resistance is the opposition to the flow of electrons.

It tries to prevent electrons from flowing. That’s why we use resistance in circuits to reduce the current and protect components such as an LED. If we tied to connect an LED directly to a nine volt battery, it would blow out because the voltage and the current are too high.

But, when we add a resistor into the circuit, then these are reduced, so the LED is protected and will shine brightly. So, given the circuit, we can increase the current by increasing the voltage.

Or we can also increase the current by reducing the resistance. We can also reduce the current by increasing the resistance. Okay, time for you to test your skills.

Can you solve these problems?

leave a comment for the answer and the solution. Problem one: Let’s say we have this lamp which has a resistance of 240 Ohms.

If we plug this into an outlet in the US, which uses 120 volts, what will the current be? Problem two: If I plug the same 240 Ohm resistive lamp into an outlet in the UK, we get a current of 0.958 Amps. So, what is the voltage being applied here?

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